@XX - Sorry, it's there now.

Posted by Sarah, Editor, eFinancialCareers

FRIDAY’S KILLER QUESTION: The Bajoran alphabet has 18 letters…

Every Friday we’ll be posting challenging and cryptic questions for you to answer, provided for us by 7city Learning. Post your answers in the comments box at the bottom of the page. Extreme deference will be accorded to the person who provides the correct answer first. We’ll add the official answer to the bottom of this article on Monday afternoon.

The Bajoran alphabet ( (from Star Trek) has 18 letters. All Bajoran words consist of 5 unique letters. The order in which the letters are written does not matter, as it does not alter the meaning of the word. As a matter of fact, any grouping of 5 unique letters would form a word in the Bajoran language.

The Romulan (again, from Star Trek) alphabet has 20 letters. All Romulan words consist of 4 unique letters. As a matter of fact, any arrangement of 4 unique letters is a word in the Romulan language.

How large are the Bajoran and Romulan vocabularies, respectively?

ANSWER:

Bajoran: Combinations of 5 out of 18; 8,568 words.

Romulan: Permutations of 4 out of 20; 116,280 words.

Comments (16)
  1. bajoran 18C5=8568
    romulan 20C4=4845

  2. Bajoran: 8568
    Romulan: 116280

  3. ” Kirk to the Enterprise…” “She cannae take anymore, captain!” ” Live long and prosper”. That’s how big it is…..

  4. 18c5 = 8568
    20c4 = 4845

    High school maths.

  5. Bajoran: 102,8160
    Romulan: 4845

  6. Would rather say
    Bajoran: 18*17*16*15*14 = 1.028mn
    Romulan: 20*19*18*17 = 116,280
    But I’m not a quant…

  7. Buy low and sell high. Who cares about this jibberish.

    The answer to your riddle is…. speak this Bajoran language with your Notting Hill M&A neighbour (so as not to get caught), thus finding out whats on the downlow and then go TRADE TO YOUR HEARTS CONTENT!

    Simples

  8. Bajoran: 8568
    Romulan: 116280

    “any grouping of 5 unique letters” (the order doesn’t matter) vs. “any ARRANGEMENT of 4 unique letters” (the order does matter)

  9. killer question! Pathetic!!!!!

  10. How large? Depends what font size they use?

  11. ..total letter universe count = n
    number of letters in a word = y

    BAJORAN
    to solve = n! / (y! x (n-y)!)
    which is 18! / (5! x 13!) = 8,568

    ROMULAN
    same method as for Bajoran, except this time letters can be arranged in any ways within the 4 letter word.

    first step:
    20! / (16! x 4!) = 4,845 (this is the number of 4 letter words where the order of the letters does not matter)

    second step:
    any four letter word can be arranged in 16 ways.
    4,845 x 16 = 77,520

    ew

  12. Follow-up to Romulan…schoolboy error, there are 24 (not 16) ways of arranging 4 letter word. Therefore 4,845 x 24 = 116,280.

    ew

  13. Bajoran – 18c5 = 8568
    Romulan – 20c4 * 4! = 116280

  14. Hey, its gone 4pm, where is it??

  15. @XX – Sorry, it’s there now.

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